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प्रश्न
If x = 3, y = 2 and z = 1; find the value of 2x – 3y + 4z + 5
योग
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उत्तर
x = 3, y = 2, z = 1
2x – 3y + 4z + 5
= 2 × 3 − 3 × 2 + 4 × 1 + 5
= 6 − 6 + 4 + 5
= 15 − 6
= 9
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