Question

If x = 2, y = 3, find x^x + y^–y.

Answer 1

Given: x = 2, y = 3

Find: x^x + y^–y

Step-wise calculation:

1. Calculate (x^x):

2² = 4

2. Calculate (y^–y):

y^–y = 3^–3

y^–y = `1/3^3`

y^–y = `1/27`

3. Add the two results:

`x^x + y^-y = 4 + 1/27`

`x^x + y^-y = 108/27 + 1/27`

`x^x + y^-y = 109/27`