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If x = –2, y = –3, find x^x + y^y. - Mathematics

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प्रश्न

If x = –2, y = –3, find xx + yy.

योग
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उत्तर

Given:

x = –2, y = –3

We need to find:

xx + yy

Step-wise calculation:

1. Calculate xx = (–2)–2:

`(-2)^-2 = 1/(-2)^2`

`(-2)^-2 = 1/4`

2. Calculate yy = (–3)–3:

`(-3)^-3 = 1/(-3)^3`

`(-3)^-3 = 1/(-27)`

`(-3)^-3 = - 1/27`

3. Add the two results:

`x^x + y^y = 1/4 + (-1/27)`

`x^x + y^y = 1/4 - 1/27`

4. Find the common denominator 4 × 27 = 108:

`27/108 - 4/108 = 23/108`

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अध्याय 6: Indices/Exponents - Exercise 6B [पृष्ठ १३१]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 6 Indices/Exponents
Exercise 6B | Q 7. | पृष्ठ १३१
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