Question

If `x+1/x = 4, "find"  x^2+1/x^2`

Answer 1

Here, `x+1/x = 4, x^2+1/x^2,`

Thus,

`4^2=x^2+1/x^2​+2`   ...`[Using (x+1/x)^2=x^2+1/x^2+2]`

16 = `x^2+1/x^2+2`

∴ `x^2+1/x^2` = 16 − (+2)

∴ `x^2+1/x^2` = 14