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प्रश्न
If \[x + \frac{1}{x} = 20,\]find the value of \[x^2 + \frac{1}{x^2} .\].
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उत्तर
Let us consider the following equation: \[x + \frac{1}{x} = 20\]
Squaring both sides, we get:
\[\left( x + \frac{1}{x} \right)^2 = \left( 20 \right)^2 = 400\]
\[ \Rightarrow \left( x + \frac{1}{x} \right)^2 = 400\]
\[ \Rightarrow x^2 + 2 \times x \times \frac{1}{x} + \left( \frac{1}{x} \right)^2 = 400 [(a + b )^2 = a^2 + b^2 + 2ab]\]
\[ \Rightarrow x^2 + 2 + \frac{1}{x^2} = 400\]
\[\Rightarrow x^2 + \frac{1}{x^2} = 398\] (Subtracting 2 from both sides)
Thus, the answer is 398.
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