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प्रश्न
If the rank correlation coefficient is 0.6 and the sum of squares of differences of ranks is 66, then find the number of pairs of observations.
योग
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उत्तर
Given : R = 0 .6, `sum "d"_1^2` = 66
R = 1 - `(6 sum "d"_1^2)/("n"("n"^2 - 1))`
`0.6 = 1 - (6 sum "d"_1^2)/("n"("n"^2 - 1))`
`0.4 = (6 xx 66)/("n"("n"^2 - 1))`
`"n"("n"^2 - 1) = (6 xx 66)/0.4`
`= (6 xx 66 xx 10)/4`
= 15 × 66 = 990
n (n - 1)(n + 1) = 990
= 10 × 9 × 11
∴ n = 10
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