Advertisements
Advertisements
प्रश्न
If the rank correlation coefficient is 0.6 and the sum of squares of differences of ranks is 66, then find the number of pairs of observations.
बेरीज
Advertisements
उत्तर
Given : R = 0 .6, `sum "d"_1^2` = 66
R = 1 - `(6 sum "d"_1^2)/("n"("n"^2 - 1))`
`0.6 = 1 - (6 sum "d"_1^2)/("n"("n"^2 - 1))`
`0.4 = (6 xx 66)/("n"("n"^2 - 1))`
`"n"("n"^2 - 1) = (6 xx 66)/0.4`
`= (6 xx 66 xx 10)/4`
= 15 × 66 = 990
n (n - 1)(n + 1) = 990
= 10 × 9 × 11
∴ n = 10
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
