Question

If the centre of the circle is (-a, -b) and radius is `sqrt("a"^2 - "b"^2)` then the equation of circle is:

विकल्प

• x² + y² + 2ax + 2by + 2b² = 0

• x² + y² + 2ax + 2by – 2b² = 0

• x² + y² – 2ax – 2by – 2b² = 0

• x² + y² – 2ax – 2by + 2b² = 0

Answer 1

x² + y² + 2ax + 2by + 2b² = 0