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If `Sqrt(3) Sin Theta = Cos Theta and Theta ` is an Acute Angle, Find the Value Of θ . - Mathematics

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प्रश्न

If `sqrt(3) sin theta = cos theta  and theta ` is an acute angle, find the value of θ .

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उत्तर

We have ,

 `sqrt(3) sin theta = cos theta`

⇒ `sin theta/ cos theta = 1/ sqrt(3)`

⇒ `tan theta = 1/ sqrt(3)`

⇒  `tan theta = tan 30°`

∴ `theta = 30°`

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अध्याय 8: Trigonometric Identities - Exercises 3

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 8 Trigonometric Identities
Exercises 3 | Q 26

संबंधित प्रश्न

Prove the following trigonometric identities.

`(cos^2 theta)/sin theta - cosec theta +  sin theta  = 0`


Prove the following trigonometric identities.

(1 + cot A − cosec A) (1 + tan A + sec A) = 2


Prove the following identities:

(1 + cot A – cosec A)(1 + tan A + sec A) = 2


Prove the following identities:

`sqrt((1 + sinA)/(1 - sinA)) = sec A + tan A`


Prove the following identities:

`sqrt((1 - cosA)/(1 + cosA)) = cosec A - cot A`


`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`


Find the value of ` ( sin 50°)/(cos 40°)+ (cosec 40°)/(sec 50°) - 4 cos 50°   cosec 40 °`


Prove that:

`(sin^2θ)/(cosθ) + cosθ = secθ`


If sin θ = `11/61`, find the values of cos θ using trigonometric identity.


Write True' or False' and justify your answer the following: 

\[ \cos \theta = \frac{a^2 + b^2}{2ab}\]where a and b are two distinct numbers such that ab > 0.


Prove the following identities:

`(tan"A"+tan"B")/(cot"A"+cot"B")=tan"A"tan"B"`


If sinA + cosA = m and secA + cosecA = n , prove that n(m2 - 1) = 2m


Without using trigonometric table , evaluate : 

`cos90^circ + sin30^circ tan45^circ cos^2 45^circ`


Prove that : `1 - (cos^2 θ)/(1 + sin θ) = sin θ`.


Prove that:

`(sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = 2/(2 sin^2 A - 1)`


Prove the following identities.

sec4 θ (1 – sin4 θ) – 2 tan2 θ = 1


Prove that `cot^2 "A" [(sec "A" - 1)/(1 + sin "A")] + sec^2 "A" [(sin"A" - 1)/(1 + sec"A")]` = 0


Prove that `(1 + sintheta)/(1 - sin theta)` = (sec θ + tan θ)2 


Complete the following activity to prove:

cotθ + tanθ = cosecθ × secθ

Activity: L.H.S. = cotθ + tanθ

= `cosθ/sinθ + square/cosθ`

= `(square + sin^2theta)/(sinθ xx cosθ)`

= `1/(sinθ xx  cosθ)` ....... ∵ `square`

= `1/sinθ xx 1/cosθ`

= `square xx secθ`

∴ L.H.S. = R.H.S.


Prove the following identity:

(sin2θ – 1)(tan2θ + 1) + 1 = 0


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