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प्रश्न
If points A(h, 0), B(0, k) and C(a, b) lie on a line then show that `"a"/"h" + "b"/"k"` = 1
योग
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उत्तर
A(h, 0), B(0, k) and C(a, b) lie on a line.
∴ A, B, C are collinear.
∴ slope of AB = slope of BC
∴ `("k" - 0)/(0 - "h") = ("b" - "k")/("a" - 0)`
∴ `- "k"/"h" = ("b" - "k")/"a"`
∴ – ak = bh – hk
∴ ak + bh = hk
∴ `("ak" + "bh")/"hk"` = 1
∴ `"a"/"h" + "b"/"k"` = 1
which is the required condition.
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