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If P(A) = 0.5, P(B) = 0.8 and P(B/A) = 0.8, find P(A/B) and P(A ∪ B)

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प्रश्न

If P(A) = 0.5, P(B) = 0.8 and P(B/A) = 0.8, find P(A/B) and P(A ∪ B)

योग
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उत्तर

Given P(A) = 0.5

P(B) = 0.8

and P(B/A) = 0.8

P(A/B) =  `("P"("A" ∩ "B"))/("P"("B"))`  .........(1)

P(B/A) = `("P"("B" ∩ "A"))/("P"("A"))`

P(A ∩ B) = P(B/A) P(A)

Substituting in equation (1) we get

(1) ⇒ P(A/B) = `("P"("B"/"A") * "p"("A"))/("P"("B"))`

= `(0.8 xx 0.5)/0.8`

P(A/B) = 0.5

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)   .........(2)

We have P(A/B) = `("P"("A" ∩ "B"))/("P"("B"))`

P(A ∩ B) = P(A/B) . P(B)

= 0.5 × 0.8

P(A ∩ B) = 0.40

(2) ⇒ P(A ∪ B) = 0.5 + 0.8 – 0.40

= 1.3 – 0.40

P(A ∪ B) = 0.90

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अध्याय 12: Introduction to probability theory - Exercise 12.3 [पृष्ठ २५८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 12 Introduction to probability theory
Exercise 12.3 | Q 4 | पृष्ठ २५८

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