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If A and B are two independent events such that P(A ∪ B) = 0.6, P(A) = 0.2, find P(B)

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प्रश्न

If A and B are two independent events such that P(A ∪ B) = 0.6, P(A) = 0.2, find P(B)

योग
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उत्तर

Given A and B are independent.

⇒ P(A ∪ B) = P(A) . P(B)

Here P(A ∪ B) = 0.6 and P(A) = 0.2

To find P(B):

Now, P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

(i.e.,) P(A ∪ B) = P(A) + P(B) – P(A) . P(B)

(i.e.,) 0.6 = 0.2 + P(B) (1 – 0.2)

P(B) (0.8) = 0.4

⇒ P(B) = `0.4/0.8`

= `4/8`

= `1/2`

= 0.5

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Introduction to probability theory - Exercise 12.3 [पृष्ठ २५८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 12 Introduction to probability theory
Exercise 12.3 | Q 3 | पृष्ठ २५८

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