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प्रश्न
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
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उत्तर
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
Q + P = (7x2 + 6xy + 2y2) + (– 12x2 – 10xy + 5y2)
= 7x2 + 6xy + 2y2 – 12x2 – 10xy + 5y2
= 7x – 12x2 + 6xy – 10xy + 2y2 + 5y2
= – 5x2 – 4xy + 7y2
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