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प्रश्न
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
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उत्तर
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
Q + P = (7x2 + 6xy + 2y2) + (– 12x2 – 10xy + 5y2)
= 7x2 + 6xy + 2y2 – 12x2 – 10xy + 5y2
= 7x – 12x2 + 6xy – 10xy + 2y2 + 5y2
= – 5x2 – 4xy + 7y2
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
z − a − b = ................
State true and false:
The value of x + 5 = 6, when x = 1
If a = 3, find the values of a2 and 2a.
Simplify:
− (− 4a − 8a)
Simplify:
2m − (3m + 2n − 6n)
Simplify:
25y − (5x − 10y + 6x − 3y)
Fill in the blank:
7x + 2z + 4y − 3 = − 3 + 4y + (.............)
Find the value of 3ab + 10bc – 2abc when a = 2, b = 5 and c = 8.
Simplify:
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Simplify:
2 (3x2 – 4x – 8) – (3 – 5x – 2x2)
