Advertisements
Advertisements
प्रश्न
If f(x) = x2 – 1, g(x) = x – 2 find a, if gof(a) = 1
Advertisements
उत्तर
f(x) = x2 – 1, g(x) = x – 2
Given gof(a) = 1
gof(x) = g(f(x))
= g(x2 – 1) = x2 – 1 – 2
= x2 – 3
gof(a) ⇒ a2 – 3 = 1
a2 = 1 + 3
= 4
a = ± 2
APPEARS IN
संबंधित प्रश्न
Using the function f and g given below, find fog and gof. Check whether fog = gof
f(x) = `(2)/x`, g(x) = 2x2 – 1
Using the function f and g given below, find fog and gof. Check whether fog = gof
f(x) = 3 + x, g(x) = x – 4
Using the function f and g given below, find fog and gof. Check whether fog = gof
f(x) = 4x2 – 1, g(x) = 1 + x
If f(x) = x2 – 1. Find fof
If f : R → R and g : R → R are defined by f(x) = x5 and g(x) = x4 then check if f, g are one-one and fog is one-one?
Consider the function f(x), g(x), h(x) as given below. Show that (fog)oh = fo(goh)
f(x) = x – 1, g(x) = 3x + 1 and h(x) = x2
Consider the function f(x), g(x), h(x) as given below. Show that (fog)oh = fo(goh)
f(x) = x2, g(x) = 2x and h(x) = x + 4
Consider the function f(x), g(x), h(x) as given below. Show that (fog)oh = fo(goh)
f(x) = x – 4, g(x) = x2 and h(x) = 3x – 5
Multiple choice question :
If f(x) = 2x2 and g(x) = `1/(3x)`, then fog is
If f(x)= x2, g(x) = 3x and h(x) = x – 2 Prove that (fog)oh = fo(goh)
