हिंदी

If F : R → R, F(X) = X3 and G: R → R , G(X) = 2x2 + 1, and R is the Set of Real Numbers, Then Find Fog(X) and Gof (X)

Advertisements
Advertisements

प्रश्न

If f : R → R, f(x) = x and g: R → R , g(x) =  2x+ 1, and R is the set of real numbers, then find fog(x) and gof (x)

योग
Advertisements

उत्तर

f : R → R and g : R → R 
∴ f (g(x)) and g(f(x)) both are defined over common domain
f(g(x))= (g(x))= (2x2 + 1)3 
= 8x+ 12x+ 6x+ 1
g(f (x)) = 2(f(x))+ 1 = 2(x3)+ 1 = 2x+ 1

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2018-2019 (March) Set 1

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

If the function f : R → R be defined by f(x) = 2x − 3 and g : R → R by g(x) = x3 + 5, then find the value of (fog)−1 (x).


Let f : W → W be defined as

`f(n)={(n-1, " if n is odd"),(n+1, "if n is even") :}`

Show that f is invertible a nd find the inverse of f. Here, W is the set of all whole
numbers.


If `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3` show that fof(x) = x, for all `x ≠ 2/3`. What is the inverse of f?


Consider f: R→ [4, ∞) given by f(x) = x2 + 4. Show that f is invertible with the inverse f−1 of given f by `f^(-1)(y) = sqrt(y - 4)`, where R+ is the set of all non-negative real numbers.


Consider f: {1, 2, 3} → {a, b, c} given by f(1) = a, f(2) = b and f(3) = c. Find f−1 and show that (f−1)−1 = f.


Consider f: `R_+ -> [-5, oo]` given by `f(x) = 9x^2 + 6x - 5`. Show that f is invertible with `f^(-1) (y) ((sqrt(y + 6)-1)/3)`

Hence Find

1) `f^(-1)(10)`

2) y if `f^(-1) (y) = 4/3`

where R+ is the set of all non-negative real numbers.


Let f = {(1, 2), (3, 5), (4, 1) and g = {(2, 3), (5, 1), (1, 3)}. Then g o f = ______ and f o g = ______.


Let f: R → R be the function defined by f(x) = sin (3x+2) ∀ x ∈ R. Then f is invertible.


Let f : N → R : f(x) = `((2"x"−1))/2` and g : Q → R : g(x) = x + 2 be two functions. Then, (gof) `(3/2)` is ____________.


If f(x) = `(3"x" + 2)/(5"x" - 3)` then (fof)(x) is ____________.


If f : R → R defind by f(x) = `(2"x" - 7)/4` is an invertible function, then find f-1.


Consider the function f in `"A = R" - {2/3}` defiend as `"f"("x") = (4"x" + 3)/(6"x" - 4)` Find f-1.


If f : R → R defined by f(x) `= (3"x" + 5)/2` is an invertible function, then find f-1.


If `f(x) = 1/(x - 1)`, `g(x) = 1/((x + 1)(x - 1))`, then the number of integers which are not in domian of gof(x) are


Let A = `{3/5}` and B = `{7/5}` Let f: A → B: f(x) = `(7x + 4)/(5x - 3)` and g:B → A: g(y) = `(3y + 4)/(5y - 7)` then (gof) is equal to


If f: A → B and G B → C are one – one, then g of A → C is


If f(x) = [4 – (x – 7)3]1/5 is a real invertible function, then find f–1(x).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×