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If f(x) = (4x + 3)/(6x – 4), x ≠ 2/3 show that fof(x) = x, for all x ≠ 2/3. What is the inverse of f?

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प्रश्न

If `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3` show that fof(x) = x, for all `x ≠ 2/3`. What is the inverse of f?

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उत्तर

It is given that `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3`

`(fof)(x) = f(f(x))`

= `f((4x+ 3)/(6x - 4))`

= `(4((4x + 3)/(6x - 4)) + 3)/(6((4x + 3)/(6x - 4)) - 4)` 

= `(16x + 12 + 18x - 12)/(24x + 18 - 24x + 16)`

= `(34x)/(34)`

= x

Therefore, fof(x) = x for all `x ≠ 2/3`.

⇒ fof  = 1

Hence, the given function f is invertible and the inverse of f is f itself.

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अध्याय 2: Functions - Exercise 2.4 [पृष्ठ ६८]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 2 Functions
Exercise 2.4 | Q 8 | पृष्ठ ६८

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