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If abca→,b→,c→ are three non-coplanar vectors represented by concurrent edges of a parallelepiped of volume 4 cubic units, find the value of abbcbccacaab(a→+b→)⋅(b→×c→)+(b→+c→)⋅(c→×a→)+(c→+a→)⋅(a→×b→)

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प्रश्न

If `vec"a", vec"b", vec"c"` are three non-coplanar vectors represented by concurrent edges of a parallelepiped of volume 4 cubic units, find the value of `(vec"a" + vec"b") * (vec"b" xx vec"c") + (vec"b" + vec"c")* (vec"c" xx vec"a") + (vec"c" + vec"a") * (vec"a" xx vec"b")`

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उत्तर

Let `vec"a", vec"b", vec"c"` be the concurrent edges of parallelepiped

Given volume of parallelepiped = 4 cubic units

`[vec"a",  vec"b",  vec"c"]` = 4

But, `[vec"a",  vec"b", vec"c"] = +-  4`

`(vec"a" + vec"b")*(vec"b" xx vec"c") = vec"a"*(vec"b" xx vec"c") + vec"b"*(vec"b" xx vec"c")`

= `[vec"a",  vec"b",  vec"c"] + [vec"b",  vec"b", vec"c"]`

= `[vec"a",  vec"b",  vec"c"]` + 0

= `[vec"a",  vec"b",  vec"c"]`  .......(1)

Similarly `(vec"b" + vec"c")*(vec"c" xx vec"a") = vec"b"*(vec"c" xx vec"a")`

= `[vec"b",  vec"c",  vec"a"]`

= `[vec"a",  vec"b",  vec"c"]`  ........(2)

`(vec"c" + vec"a")*(vec"a" xx vec"b") = vec"c"*(vec"a" xx vec"b")`

= `[vec"c",  vec"a",  vec"b"]`

= `[vec"a",, vec"b", vec"c"]`  ........(3)

So, (1) + (2) + (3) = `2[vec"a",  vec"b",  vec"c"]`

= 3(± 4)

⇒ ± 12

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Applications of Vector Algebra - Exercise 6.2 [पृष्ठ २३७]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 6 Applications of Vector Algebra
Exercise 6.2 | Q 4 | पृष्ठ २३७

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