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प्रश्न
If a, b, c are in continued proportion, prove that: a : c = (a2 + b2) : (b2 + c2)
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उत्तर
As a, b, c, are in continued proportion
Let `a/b = b/c` = k
a : c = (a2 + b2) : (b2 + c2)
⇒ `a/c = (a^2 + b^2)/(b^2 + c^2)`
L.H.S. = `a/c`
= `(ck^2)/c`
= k2
R.H.S. = `((ck^2)^2 + (ck)^2)/((ck)^2 + c^2)`
= `(c^2k^4 + c^2k^2)/(c^2k^2 + c^2)`
= `(c^2k^2(k^2 + 1))/(c^2(k^2 + 1)`
=k2
∴ L.H.S. = R.H.S.
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