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प्रश्न
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with sodium sulphite.
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उत्तर
Gas Evolved: When dilute hydrochloric acid reacts with sodium sulphite, the gas evolved is sulphur dioxide.
Reaction:
\[\ce{Na2SO3 + 2HCl -> 2NaCl + H2O + SO2 ^}\]
Chemical Test for sulphur dioxide: Pass the gas through an acidified potassium dichromate (K2Cr2O7) solution.
Observation: The solution changes color from orange to green due to the reduction of chromium from Cr6+ to Cr3+.
\[\ce{SO2 + H2O + K2Cr2O7 + H2SO4 -> Cr2(SO4)3 + K2SO4 + H2O}\]
संबंधित प्रश्न
State the inference drawn from the following observations:
Salt S is prepared by reacting dilute sulphuric acid with copper oxide. Identify S.
Give one equation to show the following properties of sulphuric acid:
Acidic nature
Which property of sulphuric acid is shown by the reaction of the concentrated sulphuric acid with ethanol?
Give reason for the following:
When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
Give reason for the following:
When carbon is heated with concentrated sulphuric acid, carbon dioxide is formed.
Describe the reaction that show
Dilute sulphuric acid behaves as dibasic acid.
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Sodium Sulphate from sodium carbonate.
State one appropriate observation of the following:
Dehydration of concentrated sulphuric acid with sugar crystals.
Give one equation to show the following property of sulphuric acid:
As a non-volatile acid
State your observation of the following case:
When dilute hydrochloric acid is added to sodium carbonate crystals.
