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प्रश्न
Give a chemical test to distinguish between dilute sulphuric acid and dilute hydrochloric acid (using lead nitrate solution).
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उत्तर १
Sulphuric acid precipitates the insoluble sulphate from lead nitrate solution.
\[\ce{Pb(NO3)2 + H2SO4 -> PbSO4 + 2HNO3}\]
Lead nitrate reacts with hydrochloric acid to give a white ppt. of lead chloride.
\[\ce{Pb(NO3)2 + 2HCl -> PbCl2 + 2HNO3}\]
उत्तर २
Bring a glass rod dipped in ammonia solution near the mouth of each test tube containing dil. HCl and dil. H2SO4 each.
The dil. HCl gives white fumes of ammonium chloride.
The dil. H2SO4 has no such fumes.
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संबंधित प्रश्न
Write balanced chemical equations to show The dehydrating property of conc. Sulphuric acid with sugar.
A, B, C, and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.
A = Typical acid property
B = Non volatile acid
C = Oxidizing agent
D = Dehydrating agent
Choose the property (A, B, C or D) depending on which is relevant to each of the following
1) Preparation of Hydrogen chloride gas
2) Preparation of Copper sulphate from copper oxide.
3) An action of conc. Sulphuric acid on Sulphur.
Give one equation to show the following properties of sulphuric acid:
As a non-volatile acid
Give reason for the following:
Sulphuric acid can form two kinds of salts with sodium chloride.
Give reason for the following:
Ammonia gas cannot be dried by passing through concentrated sulphuric acid.
Describe the reaction that show
Concentrated sulphuric acid is a dehydrating agent.
Choose the current answer from the options given below :
When conc. H2SO4 comes in contact with sugar, it becomes black due to
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Iron (II) sulphate from iron.
Write balanced equation for potassium hydrogen carbonate and dilute sulphuric acid.
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with iron (II) sulphide.
