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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

Identify rational expression should be subtracted from x2+6x+8x3+8 to get 3x2-2x+4 - Mathematics

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प्रश्न

Identify rational expression should be subtracted from `(x^2 + 6x + 8)/(x^3 + 8)` to get `3/(x^2 - 2x + 4)`

योग
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उत्तर

Let p(x) = `(x^2 + 6x + 8)/(x^3 + 8)`

p(x) − q(x) = `3/(x^2 - 2x + 4)`

`(x^2 + 6x + 8)/(x^3 + 8) - "q"(x) = 3/(x^2 - 2x + 4)`

q(x) = `(x^2 + 6x + 8)/(x^3 + 8) - 3/(x^2 - 2x + 4)`

q(x) = `(x^2 + 6x + 8)/((x + 2)(x^2 - 2x + 4)) - 3/(x^2 - 2x + 4)`

= `((x + 2)(x + 4))/((x + 2)(x^2 - 2x + 4)) - 3/(x^2 - 2x + 4)`

= `(x + 4)/(x^2 - 2x + 4) - 3/(x^2 - 2x + 4)`

= `(x + 4 - 3)/(x^2 - 2x + 4)`

= `(x + 1)/(x^2-2x+4)`

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Rational Expressions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Algebra - Exercise 3.6 [पृष्ठ १०३]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 3 Algebra
Exercise 3.6 | Q 4 | पृष्ठ १०३

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