Advertisements
Advertisements
प्रश्न
Ideal gas expands isothermally from 20 dm3 to 25 dm3 at constant pressure of 1.5 bar; then work done in dm3 bar will be ______.
विकल्प
−1.5
−5
−7.00
−7.5
MCQ
रिक्त स्थान भरें
Advertisements
उत्तर
Ideal gas expands isothermally from 20 dm3 to 25 dm3 at constant pressure of 1.5 bar; then work done in dm3 bar will be −7.5.
Explanation:
Given: Pext = 1.5
V1 = 20 dm3
V2 = 25 dm3
ΔV = V2 − V1
= 25 − 20
= 5 dm3
For expansion against a constant external pressure, the work done (W) is calculated using the following formula:
W = −Pext × ΔV
= −1.5 × 5
= −7.5 dm3 bar
∴ The work done in dm3 bar is −7.5.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2024-2025 (July) Official Board Paper
