Question

How will you prepare 1-bromopropane from propene?

Answer 1

1-Bromopropane (C₃H₇Br) can be prepared by the addition of hydrogen bromide (HBr) to propene (CH₃ – CH = CH₂) in the presence of organic peroxides. This procedure is an example of an anti-Markovnikov addition reaction. This reaction involves a free radical mechanism, where the bromine atom attaches to the terminal carbon, forming 1-bromopropane as the major product.

\[\ce{\underset{Propene}{CH3 - CH = CH2} + \underset{Hydrogen bromide}{HBr} ->[Peroxide] \underset{1-Bromopropane}{CH2 - CH2 - CH2Br}}\]