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How many three-digit numbers can be formed from the digits 0, 1, 3, 5, 6 if repetitions of digits are allowed?

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प्रश्न

How many three-digit numbers can be formed from the digits 0, 1, 3, 5, 6 if repetitions of digits are allowed?

योग
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उत्तर

A 3-digit number has 3 places which from left to right are hundred's place, ten's place, and unit's place.

Zero cannot be in the hundred's place. Hence, hundred's place can be filled in by anyone of the 4 non-zero digits 1, 3, 5, 6. Thus hundred's places can be filled in 4 ways.

Since repetition of digits is allowed, the ten's place and unit's place can be filled by anyone of the given 5 digits i.e., ten's place and unit's place can be filled in 5 different ways each.

∴ by  fundamental principle of multiplication, the total number of 3-digit numbers formed

= 4 × 5 × 5

= 100

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Permutations and Combination - Exercise 3.1 [पृष्ठ ४७]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 3 Permutations and Combination
Exercise 3.1 | Q 4. (i) | पृष्ठ ४७

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