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Evaluate nrnrn!r!(n-r)! when n = 6, r = 2 - Mathematics

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प्रश्न

Evaluate `("n"!)/("r"!("n" - "r")!)` when n = 6, r = 2

योग
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उत्तर

n = 6 , r = 2

`("n"!)/("r"!("n" - "r")!) = (6!)/(2!(6 - 2)!)`

= `(6!)/(2!4!)`

= `(6 xx 5xx 4!)/(2 xx 1 xx 4!)`

= `(6 xx 5)/2`

= 3 × 5

= 15

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.1 [पृष्ठ १६६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.1 | Q 15. (i) | पृष्ठ १६६

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