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Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 10^5 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

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प्रश्न

Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

संख्यात्मक
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उत्तर

Given: p = 760 mm Hg

K= 4.27 × 105 mm Hg

According to Henry’s law,

p = KHχ

⇒ χ = `p/K_H`

= `(760  mm  Hg)/(4.27 xx 10^(5)  mm  Hg)`

= 1.78 × 10−3

∴ Solubility in terms of mole fraction of methane in benzene is 1.78 × 103.

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अध्याय 1: Solutions - 'NCERT TEXT-BOOK' Exercises [पृष्ठ १२८]

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'NCERT TEXT-BOOK' Exercises | Q 2.35 | पृष्ठ १२८
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