हिंदी

Give two example in following case: Gaseous polar compounds

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प्रश्न

Give two example in following case:

Gaseous polar covalent compound.

Give an example in the following case:

Gaseous polar covalent compound.

अति संक्षिप्त उत्तर
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उत्तर

  1. Hydrogen chloride
  2. Water vapour
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अध्याय 2: Chemical Bonding - EXERCISE-2 [पृष्ठ ३८]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 2 Chemical Bonding
EXERCISE-2 | Q (B) 3. (c) | पृष्ठ ३८

संबंधित प्रश्न

What is graphite?


Two non-metals combine with each other by the sharing of electrons to form a compound X.

  1. What type of chemical bond is present in X?
  2. State whether X will have a high melting point or low melting point.
  3. Will it be a good conductor of electricity or not?
  4. Will it dissolve in an organic solvent or not?

Give the formulae of the chlorides of the elements X and Y having atomic numbers of 3 and 6 respectively. Will the properties of the two chlorides be similar or different? Explain your answer.


Name a neutral covalent molecule which contains one lone pair of electrons.


Electrons are getting added to an element Y: 

Is Y getting oxidised or reduced?


Covalent bonds can be single, double or triple covalent bonds. How many electrons are shared in each? Give an example of each type.


Write scientific reason.

Carbon has the property of forming many compounds.


Complete the following activity.

Write the names of the hydrocarbons for the following structural formula.

(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)

\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\phantom{..}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C- C- H}\\
\phantom{.}|\phantom{....}|\phantom{....}|\\
\ce{H - C - H}\\
|\\\ce{H}\end{array}\]
 

Give an example for each of the following statement.

A compound in which three covalent bonds are formed.


State the reasons, why carbon cannot

  1. Lose four electrons to form C4+ cation and
  2. Gain four electrons to form C4- anion.

How does carbon overcome this problem to form compounds?


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