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प्रश्न
Give reason:
Alkyl halides are generally not prepared by free radical halogenation of alkanes.
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उत्तर
Free radical halogenation of alkanes leads to the formation of a mixture of mono and poly halogen compounds. Hence, free radical halogenation of alkanes is not suitable for the preparation of alkyl halides.
संबंधित प्रश्न
Write the structure and IUPAC name of the major product in the following reaction.
\[\begin{array}{cc}
\ce{CH3 - CH - CH2Cl + NaI ->[Acetone]}\\
|\phantom{..................}\\
\ce{CH3\phantom{...............}}
\end{array}\]
Write the structure and IUPAC name of the major product in the following reaction.
\[\ce{CH3 - CH2Br + SbF3 ->}\]
Write the structure and IUPAC name of the major product in the following reaction.
\[\begin{array}{cc}
\ce{CH3 - CH - CH = CH2 + HBr ->[peroxide]}\\
|\phantom{........................}\\
\ce{CH3\phantom{.....................}}
\end{array}\]
Write the structure and IUPAC name of the major product in the following reaction.

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Amongst the following, HBr reacts fastest with
Which of the following alkyl halides has the lowest boiling point?
Which reaction is useful in exchange of halogen in alkyl chloride by iodide?
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\[\ce{R - Cl + NaI ->[acetone] R - I + NaCl ↓}\]
What is the relative rate of SN2 reaction for (CH3)3C - Br?
Identify 'A' in the following reaction: \[\ce{C2H5OH + HCl ->[A] C2H5Cl + H2O}\]
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The conversion of ethyl bromide using sodium iodide and dry acetone, this reaction is know as ______.
How is alkyl halide converted into alcohol by using?
Aqueous NaOH (or KOH)
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Complete the following reaction giving major product.
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}
\end{array}\]
Which of the following acid strengths is used to get a good yield of alkyl iodide from alcohol and sodium iodide in phosphoric acid?
