Advertisements
Advertisements
प्रश्न
Give possible expressions for the length and breadth of the rectangle whose area is given by 4a2 + 4a – 3.
Advertisements
उत्तर
Given, area of rectangle = 4a2 + 6a – 2a – 3
= 4a2 + 4a – 3 ...[By splitting middle term]
= 2a(2a + 3) – 1(2a + 3)
= (2a – 1)(2a + 3)
Hence, possible length = 2a – 1 and breadth = 2a + 3
APPEARS IN
संबंधित प्रश्न
Factorise the following using appropriate identity:
4y2 – 4y + 1
Factorise the following using appropriate identity:
`x^2 - y^2/100`
Expand the following, using suitable identity:
(3a – 7b – c)2
Factorise the following:
8a3 – b3 – 12a2b + 6ab2
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
Simplify the following:
0.76 x 0.76 - 2 x 0.76 x 0.24 x 0.24 + 0.24
Simplify the following product:
(x2 + x − 2)(x2 − x + 2)
Write in the expanded form:
`(2 + x - 2y)^2`
If \[x - \frac{1}{x} = 7\], find the value of \[x^3 - \frac{1}{x^3}\].
If 3x − 2y = 11 and xy = 12, find the value of 27x3 − 8y3
If \[a^2 + \frac{1}{a^2} = 102\] , find the value of \[a - \frac{1}{a}\].
If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]
The product (x2−1) (x4 + x2 + 1) is equal to
If 49a2 − b = \[\left( 7a + \frac{1}{2} \right) \left( 7a - \frac{1}{2} \right)\] then the value of b is
Use the direct method to evaluate :
(x+1) (x−1)
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a" + (1)/"a"`
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" - (1)/"a"`
Simplify:
(x + y - z)2 + (x - y + z)2
Simplify:
(3a - 7b + 3)(3a - 7b + 5)
