Evaluate: (3"X"+1/2)(2"X"+1/3)

Evaluate: `(3"x"+1/2)(2"x"+1/3)`

योग

`(3"x"+1/2)(2"x"+1/3)`

`=3"x"(2"x"+1/3)+1/2(2"x"+1/3)`

`=6"x"^2+"x"+"x"+1/6`

`=6"x"^2+2"x"+1/6`

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अध्याय 12: Identities - Exercise 12 (D) [पृष्ठ १५५]

अध्याय 12 Identities
Exercise 12 (D) | Q 1.1 | पृष्ठ १५५

Without actually calculating the cubes, find the value of the following:

(–12)³ + (7)³ + (5)³

Evaluate the following using identities:

(2x + y) (2x − y)

Prove that a² + b² + c² − ab − bc − ca is always non-negative for all values of a, b and c

If a - `1/a`= 8 and a ≠ 0 find :
(i) `a + 1/a (ii) a^2 - 1/a^2`

If 3x + 4y = 16 and xy = 4, find the value of 9x² + 16y².

Use the direct method to evaluate :
(3b−1) (3b+1)

Evaluate the following without multiplying:
(999)²

Evaluate, using (a + b)(a - b)= a² - b².
999 x 1001

Simplify:
(x + y - z)² + (x - y + z)²

Find the value of x³ – 8y³ – 36xy – 216, when x = 2y + 6