Advertisements
Advertisements
प्रश्न
Find the value of x3 – 8y3 – 36xy – 216, when x = 2y + 6
Advertisements
उत्तर
Here, we see that, x – 2y – 6 = 0
∴ x3 + (–2y)3 + (–6)3 = 3x(–2y)(–6) ...[Using identity, a + b + c = 0, then a3 + b3 + c3 = 3abc]
⇒ x3 – 8y3 – 216 = 36xy ...(i)
Now, x3 – 8y3 – 36xy – 216
= x3 – 8y3 – 216 – 36xy
= 36xy – 36xy ...[From equation (i)]
= 0
APPEARS IN
संबंधित प्रश्न
Factorise the following using appropriate identity:
4y2 – 4y + 1
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Simplify the following product:
(x2 + x − 2)(x2 − x + 2)
Write in the expanded form (a2 + b2 + c2 )2
Simplify the following expressions:
`(x + y - 2z)^2 - x^2 - y^2 - 3z^2 +4xy`
Find the following product:
If a + b = 6 and ab = 20, find the value of a3 − b3
If x = −2 and y = 1, by using an identity find the value of the following
If x + y + z = 8 and xy +yz +zx = 20, find the value of x3 + y3 + z3 −3xyz
If x + \[\frac{1}{x}\] = then find the value of \[x^2 + \frac{1}{x^2}\].
If a − b = 5 and ab = 12, find the value of a2 + b2
If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]
If \[x + \frac{1}{x} = 3\] then \[x^6 + \frac{1}{x^6}\] =
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
Evaluate: 20.8 × 19.2
Expand the following:
(2x - 5) (2x + 5) (2x- 3)
Expand the following:
(x - 3y - 2z)2
Simplify:
(3x + 5y + 2z)(3x - 5y + 2z)
The coefficient of x in the expansion of (x + 3)3 is ______.
