Question

From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Find the volume of the remaining solid. 

Answer 1

We have,

The height of the cylinder, H = 14 cm,

The base radius of cylinder, R = `7/2 cm `

The base radius of each conical holes, r = 2.1 cm and 

The height of each conical holes, h = 4 cm

volume of the remaining solid = volume of the cylinder - volume of 2 conical holes

`=piR^2H - 2xx1/3pir^2h`

`=22/7xx7/2xx7/2xx14-2/3xx22/7xx2.1xx2.1xx4`

= 539 - 36.96

= 502.04 cm³

So, the volume of the remaining solid is 502.04 cm³.