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From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position? - Mathematics

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प्रश्न

From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position?

योग
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उत्तर

From a committee of 8 persons, a chairman and a vice chairman are to be chosen in such a way that one person cannot hold more than one position.

Here, the number of ways of choosing a chairman and a vice chairman is the permutation of 8 different objects taken 2 at a time.

Thus, required number of ways = 

8P2 = `(8!)/((8 - 2)!)`

=`(8!)/(6!)`

= `(8 xx 7 xx 6!)/(6!)`

= 8 x 7

= 56

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अध्याय 7: Permutations and Combinations - Exercise 7.3 [पृष्ठ १४८]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 7 Permutations and Combinations
Exercise 7.3 | Q 5 | पृष्ठ १४८

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