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For the harmonic travelling wave y = 2 cos 2π (10t – 0.0080x + 3.5) where x and y are in cm and t is second.

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प्रश्न

For the harmonic travelling wave y = 2 cos 2π (10t – 0.0080x + 3.5) where x and y are in cm and t is second. What is the phase difference between the oscillatory motion at two points separated by a distance of `λ/2`

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उत्तर

Given, wave functions are y = 2 cos 2π (10t – 0.0080x + 3.5) 

= 2 cos(20πt – 0.016πx + 7π)

Now, the standard equation of a travelling wave can be written as y = a cos(ωt – kx + `phi`)

On comparing with the above equation, we get

a = 2 cm

ω = 20π rad/s

k = 0.016π

Path difference = 4 cm

Δ`phi = (2π)/λ xx (λ/2)` = π rad  .....[∵ Path difference = λ/2]

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अध्याय 15: Waves - Exercises [पृष्ठ ११२]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 15 Waves
Exercises | Q 15.36 (c) | पृष्ठ ११२

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