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Find x, if [1x1][123456325][1-23] = 0

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प्रश्न

Find x, if `[(1, "x", 1)][(1, 2, 3),(4, 5, 6),(3, 2, 5)] [(1),(-2), (3)]` = 0

योग
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उत्तर

`[(1, "x", 1)][(1, 2, 3),(4, 5, 6),(3, 2, 5)] [(1),(-2), (3)]` = 0

∴ `[(1, "x", 1)] [(1 - 4 + 9),(4 - 10 + 18),(3 - 4 + 15)]` = 0

∴ `[(1, "x", 1)] [(6),(12),(14)]` = 0

∴ [6 + 12x + 14] = [0]

∴ by equality of matrices, 12x + 20 = 0

∴ x = `-5/3`.

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अध्याय 4: Determinants and Matrices - Exercise 4.6 [पृष्ठ ९५]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 4 Determinants and Matrices
Exercise 4.6 | Q 20 | पृष्ठ ९५

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