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Find the Vector Equation of a Line Passing Through (2, −1, 1) and Parallel to the Line Whose Equations Are X − 3 2 = Y + 1 7 = Z − 2 − 3 . - Mathematics

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प्रश्न

Find the vector equation of a line passing through (2, −1, 1) and parallel to the line whose equations are \[\frac{x - 3}{2} = \frac{y + 1}{7} = \frac{z - 2}{- 3} .\]

योग
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उत्तर

We know that the vector equation of a line passing through a point with position vector  `vec a` and parallel to the vector `vec b` is  \[\vec{r} = \vec{a} + \lambda \vec{b}\] 

Here,

\[\vec{a} = 2 \hat{i} - \hat{j} + \hat{k} \]

\[ \vec{b} = 2 \hat{i} + 7 \hat{j} - 3 \hat{k} \] 

Vector equation of the required line is 

\[\vec{r} = \left( 2 \hat{i} - \hat{j} + \hat{k} \right) + \lambda \left( 2 \hat{i} + 7 \hat{j} - 3 \hat{k}  \right)\]

\[\text{ Here } , \lambda \text{ is a parameter } . \]

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अध्याय 28: Straight Line in Space - Exercise 28.1 [पृष्ठ १०]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 28 Straight Line in Space
Exercise 28.1 | Q 8 | पृष्ठ १०

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