Advertisements
Advertisements
प्रश्न
Find the value of the following:
(5−1 × 2−1) ÷ 6−1
योग
Advertisements
उत्तर
\[( 5^{- 1} \times 2^{- 1} ) \div 6^{- 1} = \left( \frac{1}{5} \times \frac{1}{2} \right) \div \frac{1}{6}\] → (a−n = 1/(an))
\[= \frac{1}{10} \times 6\]
\[= \frac{3}{5}\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Evaluate.
`{(1/3)^(-1) - (1/4)^(-1)}^(-1)`
Find the value of the following:
\[\left\{ \left( \frac{1}{3} \right)^{- 1} - \left( \frac{1}{4} \right)^{- 1} \right\}^{- 1}\]
Simplify:
\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1}\]
Simplify:
\[\left( 3^{- 1} \times 4^{- 1} \right)^{- 1} \times 5^{- 1}\]
Evaluate:
\[\left( \frac{1}{3} \right)^{- 4}\]
Simplify:
\[\left\{ \left( \frac{1}{2} \right)^{- 1} \times ( - 4 )^{- 1} \right\}^{- 1}\]
If \[x = \left( \frac{4}{5} \right)^{- 2} \div \left( \frac{1}{4} \right)^2\], find the value of x−1.
\[\left\{ \left( \frac{1}{3} \right)^2 \right\}^4\] is equal to
\[\left( \frac{2}{3} \right)^{- 5} \times \left( \frac{5}{7} \right)^{- 5}\] is equal to
Simplify and express the result in power notation with positive exponent.
(3−7 ÷ 3−10) × 3−5
