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प्रश्न
Simplify:
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उत्तर
\[\left\{ \left( \frac{2}{3} \right)^2 \right\}^3 \times \left( \frac{1}{3} \right)^{- 4} \times 3^{- 1} \times 6^{- 1}\] `=(2^2/3^2)^3xx1/(1/3)^4xx1/3xx1/6` → ((a/b)n = an/(bn)) and (a−n = 1/(an))
`=(4/9)^3xx1/(1/81)xx1/3xx1/6`
`=4^3/9^3xx81xx1/18` → ((a/b)n = an/(bn))
`=64/729xx81xx1/18`
`=64/9xx1/18`
`=64xx1/162`
`=64/162`
`=32/81`
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