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प्रश्न
Find the values of k for which the given quadratic equation has real and distinct roots:
x2 – kx + 9 = 0
योग
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उत्तर
The given equation is x2 – kx + 9 = 0
∴ D = (–k)2 – 4 × 1 × 9
= k2 – 36
The given equation has real and distinct roots if D > 0.
∴ k2 – 36 > 0
⇒ (k – 6) (k + 6) > 0
⇒ k < –6 or k > 6
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Quadratic Equations - EXERCISE 4C [पृष्ठ २०३]
