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प्रश्न
Find the values of k for which the given quadratic equation has real and distinct roots:
9x2 + 3kx + 4 = 0
योग
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उत्तर
The given equation is 9x2 + 3kx + 4 = 0
∴ D = (3k)2 – 4 × 9 × 4
= 9k2 – 144
The given equation has real and distinct roots if D > 0
∴ 9k2 – 144 > 0
⇒ 9(k2 – 16) > 0
⇒ (k – 4) (k + 4) > 0
⇒ k < –4 or k > 4
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अध्याय 4: Quadratic Equations - EXERCISE 4C [पृष्ठ २०३]
