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Find the value of the trigonometric functions for the following:sec θ = 135, θ lies in the IV quadrant

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प्रश्न

Find the value of the trigonometric functions for the following:
sec θ = `13/5`, θ lies in the IV quadrant

योग
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उत्तर

We know that sec2θ – tan2θ = 1

`(13/2)^2 - tan^2theta` = 1

`169/25 - 1` = tan2θ

tan2θ = `(169 - 25)/25 = 144/25`

tan θ = `+-  12/5`

Since θ lies in the fourth quadrant tan θ is negative.

∴ tan θ = `- 12/5`

cos θ = `1/sectheta = 5/13`

We know sin2θ + cos2θ = 1

`sin^2theta + (5/13)^2` = 1

sin2θ = `1 - 25/169`

sin2θ = `(169 - 25)/169 = 144/169`

sin θ = `+- 12/13`

Since θ lies in the fourth quadrant sin θ is negative.

∴ sin θ = `- 12/13`

sin θ = `- 12/13`, cosec θ = `1/sintheta = - 13/12`

cos θ = `5/13`, sec θ = `1/costheta = 13/5`

tan θ = `- 12/5`, cot θ = `1/tantheta = - 5/12`

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Trigonometric Functions and Their Properties
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.3 [पृष्ठ १०४]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.3 | Q 3. (v) | पृष्ठ १०४

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