Advertisements
Advertisements
प्रश्न
Find the value of the following:
sin 21° 21′
Advertisements
उत्तर
| 0' | 6' | 12' | 18' | 24' | 30' | 36' | 42' | 48' | 54' | Mean difference | ||||||||
| 0.0° | 0.1° | 0.2° | 0.3° | 0.4° | 0.5° | 0.6° | 0.7° | 0.8° | 0.9° | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |
| 49 | 0.7547 | |||||||||||||||||
From the natural cosines table
sin 21° 18′ = 0.3633
Mean difference 3' = 8
sin 21° 18′ = 0.3641
APPEARS IN
संबंधित प्रश्न
If A, B, C are the interior angles of a triangle ABC, prove that `\tan \frac{B+C}{2}=\cot \frac{A}{2}`
If sec 4A = cosec (A− 20°), where 4A is an acute angle, find the value of A.
If 4 cos2 A – 3 = 0 and 0° ≤ A ≤ 90°, then prove that cos 3 A = 4 cos3 A – 3 cos A
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A + cos A – 1 = 0
If the angle θ = –45° , find the value of tan θ.
What is the maximum value of \[\frac{1}{\sec \theta}\]
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
Sin 2A = 2 sin A is true when A =
Express the following in term of angles between 0° and 45° :
sin 59° + tan 63°
If y sin 45° cos 45° = tan2 45° – cos2 30°, then y = ______.
