Advertisements
Advertisements
प्रश्न
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
योग
Advertisements
उत्तर
For x = 1, y = 2 and z = 3
(3x3) × (−5xy2) × (2x2yz3)
(3 × 13) × (−5 × 1 × 22) × (2 × 12 × 2 × 33)
3 × (−5 × 4) × (2 × 1 × 2 × 27)
3 × (−20) × 108
= −6480
shaalaa.com
Multiplying a Polynomial by a Polynomial
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Multiply: 6x3 − 5x + 10 by 4 − 3x2
Simplify: (5a + 5b – c) (2b – 3c)
Simplify : (4x – 5y) (5x – 4y)
Simplify : (3y + 4z) (3y – 4z) + (2y + 7z) (y + z)
Evaluate (x5) × (3x2) × (-2x) for x = 1.
Evaluate: (3x – 2)(x + 5) for x = 2.
Evaluate: (2x – 5y)(2x + 3y) for x = 2 and y = 3.
Evaluate: x(x – 5) + 2 for x = 1.
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Simplify : (5 – x) (6 – 5x) (2 -x).
