Advertisements
Advertisements
प्रश्न
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
योग
Advertisements
उत्तर
For x = 1, y = 2 and z = 3
(3x3) × (−5xy2) × (2x2yz3)
(3 × 13) × (−5 × 1 × 22) × (2 × 12 × 2 × 33)
3 × (−5 × 4) × (2 × 1 × 2 × 27)
3 × (−20) × 108
= −6480
shaalaa.com
Multiplying a Polynomial by a Polynomial
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Multiply: 2y − 4y3 + 6y5 by y2 + y − 3
Simplify : (4x – 5y) (5x – 4y)
The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.
Evaluate: (3x – 2)(x + 5) for x = 2.
Evaluate: (2x – 5y)(2x + 3y) for x = 2 and y = 3.
Evaluate: xz (x2 + y2) for x = 2, y = 1 and z= 1.
Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply: 2x2 – 4x + 5 by x2 + 3x – 7
Multiply: (ab – 1) (3 – 2ab)
Simplify : (5 – x) (6 – 5x) (2 -x).
