Advertisements
Advertisements
प्रश्न
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Advertisements
उत्तर
(−3x2y2) × (x – 2y)
= (−3x2y2) × (x) − (−3x2y2)(2y)
= −3x2y2 + 6x2y3
= 6x2y3 − 3x3y2
For x = 1 and y = 2
(−3x2y2) × (x – 2y)
= (−3 × 12 × 22) × (1 − 2 × 2)
= (6 × 1 × 8) − (3 × 1 × 4)
= 48 − 12
= 36
∴ For x = 1 and y = 2, it is verified that,
(−3x2y2) × (x – 2y)
= 6x2y3 − 3x3y2
APPEARS IN
संबंधित प्रश्न
Multiply: 6x3 − 5x + 10 by 4 − 3x2
Multiply: 2y − 4y3 + 6y5 by y2 + y − 3
Simplify : (4x – 5y) (5x – 4y)
The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2. Find its area.
Evaluate (3x4y2) (2x2y3) for x = 1 and y = 2.
Evaluate (x5) × (3x2) × (-2x) for x = 1.
Evaluate: (3x – 2)(x + 5) for x = 2.
Evaluate: xz (x2 + y2) for x = 2, y = 1 and z= 1.
Evaluate: x(x – 5) + 2 for x = 1.
Multiply: (ab – 1) (3 – 2ab)
