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प्रश्न
Find the sum of the following APs:
–37, –33, –29, ... to 12 terms.
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उत्तर
–37, –33, –29, ... to 12 terms
For this A.P.,
a = –37
d = a2 – a1
= (–33) – (–37)
= –33 + 37
= 4
n = 12
We know that,
Sn = `n/2 [2a + (n - 1) d]`
S12 = `12/2 [2(-37) + (12 - 1) × 4]`
= 6[–74 + 11 × 4]
= 6[–74 + 44]
= 6(–30)
= –180
Thus, the sum of first 12 terms is –180.
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