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Find the sum of the following APs. −37, −33, −29, …, to 12 terms. - Mathematics

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प्रश्न

Find the sum of the following APs.

−37, −33, −29, …, to 12 terms.

योग
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उत्तर

−37, −33, −29, …, to 12 terms

For this A.P.,

a = −37

d = a2 − a1 

= (−33) − (−37)

= −33 + 37

= 4

n = 12

We know that,

Sn = `n/2 [2a+(n - 1) d]`

S12 = `12/2 [2(-37)+(12 - 1) × 4]`

= 6[-74 + 11 × 4]

= 6[-74 + 44]

= 6(-30)

= -180

Thus, the sum of first 12 terms is -180.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Arithmetic Progressions - Exercise 5.3 [पृष्ठ ११२]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 5 Arithmetic Progressions
Exercise 5.3 | Q 1.2 | पृष्ठ ११२
आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 11 Arithmetic Progression
Exercises 4 | Q 1.3

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