Advertisements
Advertisements
प्रश्न
Find the square of `"x"+1/"x"-1`
Advertisements
उत्तर
`("x"+1/"x"-1)^2=("x")^2+(1/"x")^2+(-1)^2+2xx"x"xx1/ "x"+2xx1/"x"xx(-1)+2(-1)xx"x"`
`="x"^2+1/"x"^2+1+2-2/"x"-2"x"`
`="x"^2+1/"x"^2+3-2/"x"-2"x"`
APPEARS IN
संबंधित प्रश्न
Expand : (a – 2b)2
Write the place name and place value of digit in the following number.
35,705
Write the place value of the underlined digit.
3,52,749
Write the following numbers in standard notation.
4000000 + 400 + 4
Represent given values in Abacus.
3 Ten crores, 7 crores, 6 ten lakhs, 7 lakhs, 4 tens and 7 ones.
Represent given values in Abacus.
Write in standard form: 7 lakhs + 5 thousands + 4 tens + 3 ones
Find the face value and place value of the digits coloured in the given numbers.
5136
The expanded form of the number 9578 is ______.
Write in expanded form:
74836
Write in expanded form:
574021
