Advertisements
Advertisements
प्रश्न
Find the square of `"x"+1/"x"-1`
Advertisements
उत्तर
`("x"+1/"x"-1)^2=("x")^2+(1/"x")^2+(-1)^2+2xx"x"xx1/ "x"+2xx1/"x"xx(-1)+2(-1)xx"x"`
`="x"^2+1/"x"^2+1+2-2/"x"-2"x"`
`="x"^2+1/"x"^2+3-2/"x"-2"x"`
APPEARS IN
संबंधित प्रश्न
Expand : (2a + b)2
Find the square of x − 2y +1
Evaluate using the expansion of (a + b)2 or (a – b)2 :
(92)2
Find the square of 391
Write the place name and place value of digit in the following number.
35,705
The expanded form of the number is given. Write the number.
20,00,000 + 3,00,000 + 60,000 + 9000 + 500 + 10 + 7
The expanded form of the number is given. Write the number.
7,00,000 + 80,000 + 4000 + 500
Find the face value and place value of the digits coloured in the given numbers.
9876
Find the face value and place value of the digits coloured in the given numbers.
4038
Write in expanded form:
8907010
