Question

Find the remainder of the following case when f(x) is divided by g(x).

f(x) = x³ + 4x² − 6x + 8, g(x) = x + 1

Answer 1

Step 1: Convert g(x) to (x – a) form

x + 1 = 0

x = − 1

Step 2: Calculate the remainder

f(–1) = (–1)³ + 4(–1)² − 6(–1) + 8

= –1 + 4(1) + 6 + 8

= –1 + 4 + 6 + 8

= 17