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Find the product: (3x – 2y) (9x^2 + 6xy + 4y^2) - Mathematics

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प्रश्न

Find the product:

(3x – 2y) (9x2 + 6xy + 4y2)

योग
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उत्तर

Given expression: (3x – 2y)(9x2 + 6xy + 4y2)

Step-wise calculation:

Multiply each term in the first bracket by each term in the second bracket:

3x × 9x2 = 27x3

3x × 6xy = 18x2y

3x × 4y2 = 12xy2

–2y × 9x2 = –18x2y

–2y × 6xy = –12xy2

–2y × 4y2 = –8y3

Now, add these terms together:

27x3 + 18x2y + 12xy2 – 18x2y – 12xy2 – 8y3

Combine like terms:

27x3 + (18x2y – 18x2y) + (12xy2 – 12xy2) – 8y3

Simplifies to:

27x3 – 8y3

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अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
Exercise 3A | Q 12. (i) | पृष्ठ ६४
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